private function hasDuplicates(arr:Array):Boolean{
02
03 var x:uint;
04 var y:uint;
05
06 for (x = 0; x < arr.length ; x++){
07
08 for (y = x + 1; y < arr.length; y++){
09
10 if (arr[x] === arr[y]){
11 return true;
12 }
13
14 }
15 }
16 return false;
17 }

Need to give a credit to author, i found it here:

http://myprogrammingblog.com/2011/12/12/actionscript-3-0-how-to-find-duplicate-array-elements-solved/

actually I am trying to do same but little bit diff… I want unique value from array elements. I don’t want to repeat those values having same starting character.

var mainArr:Array = ["cat","dog","chocolate","fire","food","house","market","butter",
"fruit","ham","computer","door","hen"]
// c,d,f,m,b,h = 6
removeDuplicate(mainArr);

function removeDuplicate(arr:Array) : void{
var i:int;
var j: int;
for (i = 0; i < arr.length; i++){
for (j = i + 1; j < arr.length; j++){
if (arr[i].substr(0,1) == arr[j].substr(0,1)){
arr.splice(j,1);
}
}
}
trace(arr)
trace(arr.length)
}

Neil

var originalArray:Array = new Array(“yellow”, “red”, “blue”, “red”, “yellow”, “green”, “yellow”, “purple”, “ginger”, “red”, “blue”);

var dedupedArray:Array = new Array();

function ArrayTest()
{
for each (var colour:String in originalArray)
{
if (dedupedArray.indexOf(colour)===-1)
{
dedupedArray.push(colour);
}
}
trace(“dedupedArray: “+dedupedArray);
}

ArrayTest();